'''
Software Tools Exam 2 Question 2:
Write a program to convert numbers to letters and output the sum of the letters from 0 to 999. For example, 342 should be converted to "three hundred forty two",
then sums the letters of each word ---> three hundred forty two = 5 + 7 + 5 + 3 = 20
'''
import sys

def main():
    # Define output array
    output_lst = ["", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
    ten_lst = ["ten", "eleven", 'twelve', 'thirteen', 'fourteen', 'fifteen', 'sixteen', 'seventeen', 'eighteen', 'nineteen']
    tens_lst = ['','','twenty','thirty','forty','fifty','sixty','seventy','eighty','ninety']
    hundreds_lst = ['hundred']
    out_string = ""; sumed = 0
    # Define counter var to get place (ones, tens, hundreds)
    counter = 0;
    # Define list var to store values
    char_lst = []
    # Iterate over values 
    for input_val in range (0,1000):
        # Print current iteration
        print '--------------------------------------------------'
        print 'INPUT VAL: %d ' % (input_val)
        # Reset counter var
        counter = 0
        # Check for zero:
        if (input_val == 0):
            # Zero's value is 4, so just add 4 and keep going 
            print 'Zero => sum 4'
            sumed +=4
            continue
        # Check for additional tens spots
        while (input_val / 10.0 >= 1):
            # Increment counter (One additional spot found)
            counter+=1
            # Append the last digit to the list
            char_lst.append(input_val % 10)
            input_val = input_val/10
        # Get total tens spots (stored in counter)
        counter+=1
        # Get final array element
        char_lst.append(input_val % 10)
        # Reverse array so it's in standard order (hundreds,tens,ones)
        char_lst.reverse()
        print char_lst
        for x in char_lst:
            # Hundreds place first
            if counter == 3:
                # The lists are specially formatted such that the index of the number is the string value of the number. Index[3] = three, hundreds[0] = 'hundred'
                out_string += (output_lst[x] + ' ' + hundreds_lst[0]+' ')
                # Add string size to running total and print
                sumed += len(output_lst[x] + hundreds_lst[0])
                print "%s %s sum %d" % (output_lst[x], hundreds_lst[0], sumed)
            # Tens place next
            elif counter == 2:
                # Check for teens spot with some tricky conversions, and check for length so we don't get an index error
                if len(char_lst) == 3:
                    # Check if number is a teen
                    if int(str(char_lst[1]) + str(char_lst[2])) in range(10,20):
                        # Use special teen list to print result, and break so the ones digit doesn't reprint
                        sumed += len(ten_lst[char_lst[2]])
                        out_string += ten_lst[char_lst[2]]
                        print "%s, total sum %d" % (ten_lst[char_lst[2]], sumed)
                        counter = 0
                        break
                # Easier to program in an if statement than it is to retake modulus and make it all one case
                elif len(char_lst) == 2:
                    if int(str(char_lst[0]) + str(char_lst[1])) in range(10,20):
                        # Use special teen list to print result, and break so the ones digit doesn't reprint
                        sumed += len(ten_lst[char_lst[1]])
                        out_string += ten_lst[char_lst[1]]
                        print "%s, total sum %d" % (ten_lst[char_lst[1]], sumed)
                        counter = 0
                        break
                # Else it's not a special teen, so just perform as normal
                out_string += (tens_lst[x] + ' ')
                sumed += len(tens_lst[x])
                print "%s, total sum %d" % (tens_lst[x], sumed)            
            # Ones place final
            else: 
                # Index[x] = long_string(x)
                out_string +=(output_lst[x])
                sumed += len(output_lst[x])
                print "%s, total sum %d" % (output_lst[x], sumed)
            counter -= 1
        # Clear number list on every iteration
        char_lst = []
        # Print final result
        print "total sum is %d" % (sumed)
        # Repeat loop for next input
        


# boiler plate code
if __name__ == '__main__':
    main()